SOLUTION: The solution in the large container was 60% alcohol, and the solution in the small container as only 30% alcohol. How much of each should be used to get 300mL that is 42% alcohol?

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Question 1078599: The solution in the large container was 60% alcohol, and the solution in the small container as only 30% alcohol. How much of each should be used to get 300mL that is 42% alcohol?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, volume of the 30% alcohol from small container
300-x, volume of the 60% alcohol

30x%2B60%28300-x%29=42%2A300

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180 ml. of the 30% alcohol
120 ml. of the 60% alcohol