Question 1077037: How many gallons of a 10% salt solution must be mixed with 50 gallons of a 50% salt solution to obtain a 20% salt solution? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x=10%
.10(x)+.50(50)=.20(50+x)
.10x+25=10+.20x
-.10x=-15
x=150 gallons of 10% salt.
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To go from 50% to 20% is 3/4 of the way to 10%
150 gallons of the final 200 gallon mixture is 3/4 of the mixture.