SOLUTION: A goldsmith has two gold alloys. The first alloy is 30% gold; the second alloy is 80% gold. How many grams of each should be mixed to produce 50 grams of an alloy that is 68% gold?
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Question 1076102: A goldsmith has two gold alloys. The first alloy is 30% gold; the second alloy is 80% gold. How many grams of each should be mixed to produce 50 grams of an alloy that is 68% gold?
amount of 30% gold _______grams
amount of 80% gold _______grams Found 3 solutions by Alan3354, josmiceli, jorel1380:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! amount of 30% gold _______grams
amount of 80% gold _______grams
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Don't type this.
It's irritating and serves no purpose.
You can put this solution on YOUR website! Let = grams of 30% gold needed
Let = grams of 80% gold needed
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(1)
(2)
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(2)
(2)
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Multiply both sides of (1) by and
subtract (1) from (2)
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(2)
(1)
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and
(1)
(1)
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12 grams of 30% gold are needed
38 grams of 80% gold are needed
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check:
(2)
(2)
(2)
(2)
(2)
OK
You can put this solution on YOUR website! Let n be the amount of 80% alloy. Then the 30% alloy is 50-n. So:
.8n+.3(50-n)=.68(50)
.5n+15=34
.5n=19
n=38
He needs 38 gms of 80% alloy, and 12 gms 30% alloy. ☺☺☺☺
