SOLUTION: In the lab, Raina has two solutions that contain alcohol and is mixing them with each other. She uses 40 milliliters less of solution A than solution B. Solution S is 10% alcohol a
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Question 1075678: In the lab, Raina has two solutions that contain alcohol and is mixing them with each other. She uses 40 milliliters less of solution A than solution B. Solution S is 10% alcohol and solution B is 14% alcohol. How many milliliters of solution B does she use, if the resulting mixture has 176 milliliters of pure alcohol? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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In the lab, Raina has two solutions that contain alcohol and is mixing them with each other.
She uses 40 milliliters less of solution A than solution B.
Solution A is 10% alcohol and solution B is 14% alcohol.
How many milliliters of solution B does she use, if the resulting mixture has 176 milliliters of pure alcohol?
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The solution by "josgarithmetic" is .
Below find the correct solution.
Let V be the volume of the solution B in milliliters (the value under the question).
Then the volume of the solution A is (V-40) milliliters, according to the condition.
The solution A contains 0.1*(V-40) milliliters of pure alcohol.
The solution B contains 0.14*V milliliters of pure alcohol.
The mixture of the solutions A and B contains 0.1*(V-40) + 0.14*V of pure alcohol.
Therefore, your equation is
0.1*(V-40) + 0.14*V = 176.
Simplify and solve for V.
0.1*V - 0.04 + 0.14*V = 176,
0.24*V = 180 ---> V = = 750.
Answer. 750 milliliters of the solution A.
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