SOLUTION: Mixture of Chemicals
a) Solve using one variable. Petrochemicals worth $6/L are mixed with 40 L of another solution values at $9/L to produce a mixtures worth $7.20/L. How many
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a) Solve using one variable. Petrochemicals worth $6/L are mixed with 40 L of another solution values at $9/L to produce a mixtures worth $7.20/L. How many
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Question 1073421: Mixture of Chemicals
a) Solve using one variable. Petrochemicals worth $6/L are mixed with 40 L of another solution values at $9/L to produce a mixtures worth $7.20/L. How many liters of the petrochemicals are used?
b) Solve using two variables. Petrochemicals worth $6/L are mixed with other chemicals worth $9/L to produce 100 L of chemicals worth 47.65/L. How many liters of each are used? Answer by josgarithmetic(39617) (Show Source):
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