SOLUTION: A jogger starts from one end of a 16-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A jogger starts from one end of a 16-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the      Log On

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Question 1072095: A jogger starts from one end of a 16-mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the jogger is 5 mph and the rate of the cyclist is 10 mph, at what time will the two meet?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The cyclist begins when the distance between him and jogger was 11 miles. Start time is 9AM when they are 11 miles from each other.
               speed     time    distance
Jogger          5         t      5t    
Cyclist         10        t      10t
Total                            11


5t%2B10t=11
15t=11
t=11%2F15

t=%2811%2F15%29%284%2F4%29=44%2F60------HOURS
or same as
44 minutes

They meet at 9:44 AM.