SOLUTION: Two cyclists start from the same point and ride in opposite directions. One cyclist rides twice as fast as the other. In 3 h, they are 108 mi apart. Find the rate of each cyclist
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Question 1071798: Two cyclists start from the same point and ride in opposite directions. One cyclist rides twice as fast as the other. In 3 h, they are 108 mi apart. Find the rate of each cyclist Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Distance(d) equals rate(r) times time(t) or d=rt; r=d/t and t=d/r
Let r=rate of first cyclist
Then 2r=rate of second cyclist
Distance first cyclist travels in 3 hours: d1=3r
Distance second cyclist travels in 3 hours:d2=3*2r=6r
Sooooo 3r + 6r=108
9r=108
r=12 mi/hr
2r=2*12=24 mi/hr
CK
3*12+3*24=108
36+72=108
108=108
Hope this helps---ptaylor
