SOLUTION: Two gasohol mixtures are available, one with 6.35% alcohol and the other with 11.28% alcohol. How many litres of the 6.35% mixture must be added to 26.1 L of the other mixture to m

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Question 1070593: Two gasohol mixtures are available, one with 6.35% alcohol and the other with 11.28% alcohol. How many litres of the 6.35% mixture must be added to 26.1 L of the other mixture to make a final mixture containing 8.00% alcohol?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of the 6.35% mixture needed
+.0635x+ = liters of alcohol in 6.35% mixture
+.1128%2A26.1+=+2.94408+ = liters of alcohol in 11.28% mixture
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+%28+.0635x+%2B+2.94408+%29+%2F+%28+x+%2B+26.1+%29+=+.08+
+.0635x+%2B+2.94408+=+.08%2A%28+x+%2B+26.1+%29+
+.0635x+%2B+2.94408+=+.08x+%2B+2.088+
+.0165x+=+.85608+
+x+=+51.88364+
51.884 liters of the 6.35% mixture is needed
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check:
+%28+.0635x+%2B+2.94408+%29+%2F+%28+x+%2B+26.1+%29+=+.08+
+%28+.0635%2A51.884+%2B+2.94408+%29+%2F+%28+51.884+%2B+26.1+%29+=+.08+
+%28+3.29463+%2B+2.94408+%29+%2F+77.984+=+.08+
+6.23871+%2F+77.984+=+.08+
+.0799999+=+.08+
close enough