SOLUTION: A homeowner wants to spread 200 pounds of a grass seed mixture that is 50% bluegrass. The local hardware store has on hand a mixture that is 90% bluegrass and a mixture that is 20

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Question 1069662: A homeowner wants to spread 200 pounds of a grass seed mixture that is 50% bluegrass. The local hardware store has on hand a mixture that is 90% bluegrass and a mixture that is 20% bluegrass. How many pounds of each mixture does the homeowner buy to make the 200 pounds of 50% mix?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
x of the 20%
y of the 90%
Also good, y=200-x, of the 90% Bluegrass

%2820x%2B90%28200-x%29%29%2F200=50
Solve for x and evaluate 200-x.


using one variable for a two part mixture problem

Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.
There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems