SOLUTION: 12 quarts of an acid solution was mixed with 3 quarts of pure water to make it 52% solution. Find the percent concentration of the first solution.
Question 1068681: 12 quarts of an acid solution was mixed with 3 quarts of pure water to make it 52% solution. Find the percent concentration of the first solution. Found 2 solutions by addingup, ikleyn:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 12 quart of x solution mixed with 3 quarts of 1 solution (1 is 100%, it's 100% water)
So our total will be 12+3 = 15 and we want a 0.52 solution
:
12x+3(1) = 15(0.52)
12x+3 = 7.8
12x = 4.8
x = 0.4
the 12 quarts are a 40% solution
You can put this solution on YOUR website! .
12 quart of x solution mixed with 3 quarts of pure water (0 is 0%, it's 0% acid solution).
So our total will be 12+3 = 15 and we want a 0.52 solution
:
12x + 3*0 = (12+3)*0.52
12x = 7.8
x = 0.65
the 12 quarts are a 65% solution.
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Solved. The solution by the other tutor is wrong. It produces an "impossible" answer.
