SOLUTION: Please help with mixture problem. I can't figure out how to get the equation. Thanks!
A chemist needs 70mL of a 32% solution, but has only 26% and 47% solutions available. Find
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A chemist needs 70mL of a 32% solution, but has only 26% and 47% solutions available. Find
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Question 1066435: Please help with mixture problem. I can't figure out how to get the equation. Thanks!
A chemist needs 70mL of a 32% solution, but has only 26% and 47% solutions available. Find how many mL of each that should be mixed to get the desired solution. Found 2 solutions by Edwin McCravy, josmiceli:Answer by Edwin McCravy(20056) (Show Source):
A chemist needs 70mL of a 32% solution, but has only 26% and
47% solutions available. Find how many mL of each that should
be mixed to get the desired solution.
An N% solution is some liquid which is N% pure stuff and the
rest water. Make this chart:
| mL | % |mL of
| of | as |pure
|liquid|decimal|stuff
-------------------------------------------
Weaker solution | x | 0.26 |0.26*x
Stronger solution | y | 0.47 |0.47*y
-------------------------------------------
Desired solution | 70 | 0.32 |0.32*70
The equations come from the two end columns:
The second equation simplifies to
26x + 47y = 2240
solve for x and y.
Edwin
You can put this solution on YOUR website! Let = ml of 26% solution needed
Let = ml of 47% solution needed
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(1)
(2)
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(2)
(2)
(2)
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Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
----------------------------
and
(1)
(1)
-----------------------
50 ml of 26% solution are needed
20 ml of 47% solution are needed
-------------------------------
check:
(2)
(2)
You can finish this check
