SOLUTION: A coffee manufacturer wants to market a new blend 100 pounds of coffee that sells for $3.90 per pound by mixing coffee#1 and coffee #. Coffee #1 sells for $2.75 per pound and coff

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A coffee manufacturer wants to market a new blend 100 pounds of coffee that sells for $3.90 per pound by mixing coffee#1 and coffee #. Coffee #1 sells for $2.75 per pound and coff      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1066268: A coffee manufacturer wants to market a new blend 100 pounds of coffee that sells for $3.90 per pound by mixing coffee#1 and coffee #. Coffee #1 sells for $2.75 per pound and coffee #2 sells for $5.00 per pound. What amounts o each coffee should be blended to obtain the desired blend/mixture. Round answer to nearest pound.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Let X = the number of pounds of $2.70 coffee and 
let Y = the number of pounds of $5.00 coffee.

When he mixes them together he will have X+Y pounds of coffee,
so we have the equation

X+Y = 100

If he could sell the X pounds of $2.75 coffee without mixing it, 
it would bring him in 2.75X dollars.

If he could sell the Y pounds of $5.00 coffee without mixing it, 
it would bring him in 5.00Y dollars.

So if he sold them both without mixing them they would bring him in
a total of 2.75X + 5.00Y dollars.

But if he mixed them together and sold them he would have 100 pounds 
of coffee selling for $3.90 per pound and that would bring him in 390
dollars.

So the other equation comes from setting the amount he would take in
if he could sell them separately equal to the amount he would take in
if he mixes them first.

 2.75X + 5.00Y = 390

So we have the system:

system%28X%2BY=100%2C2.75X+%2B+5Y=390%29

Solve that system of equations and get:

He would mix 48%268%2F9 pounds of the cheaper coffee and 51%261%2F9 pounds
of the more expensive coffee.

Edwin