SOLUTION: A chemist wants to mix 10% alcohol solution and a 20% alcohol solution to make a 12% alcohol solution. How many cups of each solution must be mixed to make 5 cups of the 12% soluti
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Question 1060821: A chemist wants to mix 10% alcohol solution and a 20% alcohol solution to make a 12% alcohol solution. How many cups of each solution must be mixed to make 5 cups of the 12% solution? Answer by ikleyn(52794) (Show Source):
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A chemist wants to mix 10% alcohol solution and a 20% alcohol solution to make a 12% alcohol solution.
How many cups of each solution must be mixed to make 5 cups of the 12% solution?
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OK, let us measure the volume in cups. Why not?
Let "n" be the number of cups of the 10% solution.
Then the number of the 20% solution is 5-n.
The "alcohol content" equation is
= 0.12, or
0.1n + 0.2*5 - 0.2n = 5*0.12,
-0.1n = 0.6 - 1.0,
-0.1n = -0.4,
n = = 4.
Answer. 4 cups of the 10% solution must be mixed with 5-4 = 1 cup of the 20% solution.
