SOLUTION: A scientist mixes water (containing no salt) with a solution that contains
30% salt. She wants to obtain 210 ounces of a mixture that is 15%
salt. How many ounces of water and h
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A scientist mixes water (containing no salt) with a solution that contains
30% salt. She wants to obtain 210 ounces of a mixture that is 15%
salt. How many ounces of water and h
Log On
Question 1057134: A scientist mixes water (containing no salt) with a solution that contains
30% salt. She wants to obtain 210 ounces of a mixture that is 15%
salt. How many ounces of water and how many ounces of the 30% salt solution should she use? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
The way that tutor ikleyn responded is just like what the video posted/linked above would show, so these are both now examples of how to do such a two-part mixture problem using one single variable.
You can put this solution on YOUR website! .
A scientist mixes water (containing no salt) with a solution that contains
30% salt. She wants to obtain 210 ounces of a mixture
that is 15% salt. How many ounces of water and how many ounces of the 30% salt solution should she use?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Let W = the volume of water to be mixed in ounces).
Then the volume of the 30% salt solution needed is (210-W).
The balance equation for the salt mass is
0.3*(210-W) = 0.15*210.
Simplify and solve for W:
63 - 0.3W = 31.5,
63 - 31.5 = 0.3W,
0.3W = 31.5,
W = = 105.
Answer. 105 ounces of water is needed.
(