SOLUTION: A container holds 5 gallon of a gas oil mixture in a 50:1 ratio (gas to oil). How many fl oz of oil should be added to change the mixture into a 40:1 mix? (1 gallon=128 fl oz).

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Question 1053659: A container holds 5 gallon of a gas oil mixture in a 50:1 ratio (gas to oil). How many fl oz of oil should be added to change the mixture into a 40:1 mix? (1 gallon=128 fl oz).
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The fraction of oil to total mixture is:
+1%2F51+
+%281%2F51%29%2A5%2A128+=+640%2F51+ fl oz of oil
------------------
+%28+640%2F51+%2B+x+%29+%2F+%28+640+%2B+x+%29+=+1%2F41+
+640%2F51+%2B+x+=+%281%2F41%29%2A%28+640+%2B+x+%29+
+640%2F51+%2B+x+=+640%2F41+%2B+x%2F41+
Multiply both sides by +41%2A51+
+41%2A640+%2B+41%2A51%2Ax+=+51%2A640+%2B+51x+
+40%2A51%2Ax+=+10%2A640+
++2040x+=+6400+
+x+=+3.13725+ fl oz of oil shouyld be added
check:
+1%2F40+=+%28+12.54902+%2B+3.13725+%29+%2F+%28+640+-+12.54902+-+3.13725+%29+
+1%2F40+=+15.68627+%2F+624.31373+
+1%2F40+=+.02512562+
+1+=+1.00502+
I expected to be closer
Check my work