SOLUTION: There is a total of $2.40 in change. There are X number of quarters. There are 4 times as many nickels as quarters. There are 4 times as many quarters + 7 additional dimes for t

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Question 1053604: There is a total of $2.40 in change. There are X number of quarters. There are 4 times as many nickels as quarters. There are 4 times as many quarters + 7 additional dimes for total dimes. How many of each quarters, nickels, and dimes are there? I know the answer is 2 quarters, 8 nickels, and 15 dines, but I cannot figure it our algebraically.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+x+ = the number of quarters
+4x+ = the number of nickels
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+4x+%2B+7+ = the number of dimes
( I think. The wording is vague to me. )
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+25x+%2B+5%2A%284x%29+%2B+10%2A%28+4x+%2B+7+%29+=+240+ ( in cents )
+25x+%2B+20x+%2B+40x+%2B+70+=+240+
+85x+=+170+
+x+=+2+
and
+4x+=+8+
and
+4x+%2B+7+=+4%2A2+%2B+7+
+4x+%2B+7+=+15+
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There are 2 quarters, 8 nickels, and 15 dimes
I guess I got it.