SOLUTION: A metallurgist has one alloy containing 30% copper and another containing 67% copper. How many pounds of each alloy must he use to make 45 pounds of a third alloy containing 45% co
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Question 1053200: A metallurgist has one alloy containing 30% copper and another containing 67% copper. How many pounds of each alloy must he use to make 45 pounds of a third alloy containing 45% copper? (Round to two decimal places if necessary.)
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.67x + .30(45lbs-x) = .45(45lbs)
x = .15(45lbs)/.37 , amount containing 67% copper , amount containing 30% copper
