SOLUTION: Help one more time or maybe 2 at the most. I hate word problems!!
A photographer is mixing a 5% acetic acid solution with a 10% acetic solution to get 5 liters of a 7%solution. H
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A photographer is mixing a 5% acetic acid solution with a 10% acetic solution to get 5 liters of a 7%solution. H
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Question 1052401: Help one more time or maybe 2 at the most. I hate word problems!!
A photographer is mixing a 5% acetic acid solution with a 10% acetic solution to get 5 liters of a 7%solution. How many liters of the 5 % and 10%solutions should she add? Show work
HELP!! Found 2 solutions by ankor@dixie-net.com, ikleyn:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A photographer is mixing a 5% acetic acid solution with a 10% acetic solution to get 5 liters of a 7%solution.
How many liters of the 5 % and 10%solutions should he add?
:
let x = amt of 10% solution
the results is 5 liters, therefore
(5-x) = amt of 5% solution
:
.10x + .05(5-x) = .07(5)
.10x + .25 - .05x = .35
.10x - .05x = .35 - .25
.05x = .10
x = .10/.05
x = 2 liters of the 10% solution
then obviously
5 - 2 = 3 liters of the 5% solution
