SOLUTION: A drink is one-third syrup and the rest water. If six ounces of water were added, it would become 20% sure. How many ounces of total liquid (water plus syrup) were in the original

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Question 1048774: A drink is one-third syrup and the rest water. If six ounces of water were added, it would become 20% sure. How many ounces of total liquid (water plus syrup) were in the original mixture?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = total ounces of
liquid in original mixture
+%281%2F3%29%2Ax+ = ounces of syrup
in original mixture
+%282%2F3%29%2Ax+ = ounces of water
in original mixture
-------------------------------
+%28+%281%2F3%29%2Ax+%29+%2F+%28+x+%2B+6+%29+=+.2+
+%281%2F3%29%2Ax+=+.2%2A%28+x+%2B+6+%29+
+x+=+.6%2A%28+x+%2B+6+%29+
+x+=+.6x+%2B+3.6+
+.4x+=+3.6+
+x+=+36%2F4+
+x+=+9+
9 ounces of liquid were in original mixture
----------------
check:
+%28+%281%2F3%29%2Ax+%29+%2F+%28+x+%2B+6+%29+=+.2+
+%28+%281%2F3%29%2A9+%29+%2F+%28+9+%2B+6+%29+=+.2+
+3+%2F+15+=+.2+
+3+=+.2%2A15+
+3+=+3+
OK