SOLUTION: How many liters of a 25% antifreeze solution should be mixed with a 40% antifreeze solution to make 6 liters of a 30% antifreeze solution?

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Question 1047505: How many liters of a 25% antifreeze solution should be mixed with a 40% antifreeze solution to
make 6 liters of a 30% antifreeze solution?
Answer by ikleyn(52788) About Me  (Show Source):
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How many liters of a 25% antifreeze solution should be mixed with a 40% antifreeze solution to
make 6 liters of a 30% antifreeze solution?
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Let V be the volume of the 25% antifreeze solution to be mixed.

Then

0.25V + 0.4(6-V) = 0.3*6,  or

0.25V + 2.4 - 0.4V = 1.8,  or

-0.15V = -0.6,  V = -0.6%2F0.15 = 4.

Answer.  4 liters of the 25% antifreeze solution.

There is entire bunch of the lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - OVERVIEW of lessons on word problems for mixtures
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

It contains many other solved word problems, as well as many other interesting and useful things.