SOLUTION: Jet left Edmonton at 4:00 P.M. traveling west at 116 km/h. one hour later ( 5:00 PM ) Ahmed left Edmonton travelling east at 84 km/h. At what time will they be 316 km apart?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Jet left Edmonton at 4:00 P.M. traveling west at 116 km/h. one hour later ( 5:00 PM ) Ahmed left Edmonton travelling east at 84 km/h. At what time will they be 316 km apart?      Log On

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Question 1046003: Jet left Edmonton at 4:00 P.M. traveling west at 116 km/h. one hour later ( 5:00 PM ) Ahmed left Edmonton travelling east at 84 km/h. At what time will they be 316 km apart?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
How far does Jet get in the 1st hour?
+d%5B1%5D+=+116%2A1+
+d%5B1%5D+=+116+
Let +t+ = time in hrs after Ahmed leaves
until they meet. Start a stopwatch when Ahmed leaves
Let +d+ = distance in km that Ahmed travels
until they meet
------------------------
Ahmed's equation:
(1) +d+=+84t+
Jet's equation:
(2) +316+-+d+-+116+=+116t+
----------------------------
Plug (1) into (2)
(2) +316+-+84t+-+116+=+116t+
(2) +200t+=+200+
(2) +t+=+1+
-----------------
5 PM + 1 = 6 PM
They will be 316 mi apart at 6 PM
---------------------------------
check:
(1) +d+=+84t+
(1) +d+=+84%2A1+
(1) +d+=+84+
and
(2) +316+-+d+-+116+=+116t+
(2) +316+-+d+-+116+=+116%2A1+
(2) +200+-+d+=+116+
(2) +d+=+84+
OK