SOLUTION: A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution. How many liters of 12% solution must be added?
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Question 1045917: A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution. How many liters of 12% solution must be added? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution.
How many liters of 12% solution must be added?
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Let x be the volume of the 12% solution to be mixed.
Then the total volume of the liquid will be (16+x) liters.
The amount of pure acetic acid in 16 liters of the 7% solution is 0.07*16.
The amount of pure acetic acid in x liters of the 12% solution is 0.12*x.
The amount of pure acetic acid in (16+x) liters of the mixture will be (0.07*16 + 0.12*x).
The concentration condition for the mixture requires
= 0.09*(16+x).
It is your equation to solve for x. Simplify it step by step
1.12 + 0.12x = 1.44 + 0.09x,
0.12x - 0.09x = 1.44 - 1.12,
0.03x = 0.32,
x = = .
Answer. liters of the 12% solution must be added.
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