SOLUTION: 5 oz. of a 2% alcohol solution was mixed with 11 oz. of a 66% alcohol solution. Find the concentration of the new mixture

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Question 1045139: 5 oz. of a 2% alcohol solution was mixed with 11 oz. of a 66% alcohol solution. Find the concentration of the new mixture
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
5 oz. of a 2% alcohol solution was mixed with 11 oz. of a 66% alcohol solution. Find the concentration of the new mixture
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The amount of the pure alcohol in the mixture is  (0.02*5 + 0.66*11) oz.

The volume of the mixture is (5 + 11) oz.

The concentration of the mixture is %28%280.02%2A5+%2B+0.66%2A11%29%2F%285+%2B+11%29%29%2A100 percents.

Calculate.



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the concentration of the new mixture
as a decimal
-----------------
+%28+.02%2A5+%2B+.66%2A11+%29+%2F+%28+5+%2B+11+%29+=+x+
+%28+.1+%2B+7.26+%29+%2F+16+=+x+
+7.36+%2F+16+=+x+
+x+=+.46+
The concentration of the new mixture is 46%