Question 1039778: Hi can someone please help me.
If 6 is subtracted from the third of three consecutive odd integers and the result is multiplied by 2, the answer is 23 less than the sum of the first and twice the second of the integers. Find the integers.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! let x be the first odd integer, then we have
:
x, x+2, x+4
:
(x+4 - 6) * 2 = x + 2(x+2) - 23
:
2x - 4 = 3x - 19
:
x = 15
:
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the integers are 15, 17, 19
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