SOLUTION: Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution? A. 5.5 l B. 11 L C. 16.5 L D. 22 L

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution? A. 5.5 l B. 11 L C. 16.5 L D. 22 L      Log On

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Question 1033593: Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution?
A. 5.5 l
B. 11 L
C. 16.5 L
D. 22 L
Answer by Alan3354(69443) About Me  (Show Source):
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Ricky adds 11L of water to a 60.5% solution of alcohol in water. If the new concentration is 36.3%, how much was the original solution?
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S = amount of 60.5% solution
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S*60.5 + 11*0 = (S + 11)*36.3
60.5S = 36.3S + 399.3
24.2S = 399.3
S = 16.5 liters