SOLUTION: You need a 80% alcohol solution. On hand, you have a 225 mL of a 15% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain
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Question 1033211: You need a 80% alcohol solution. On hand, you have a 225 mL of a 15% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain the desired solution? Found 2 solutions by josmiceli, mananth:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = ml of 95% solution needed = ml of alcohol in 95% solution = ml of alcohol in 15% solution
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975 ml of the 95% solution is needed
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check:
OK
You can put this solution on YOUR website! -------------- percent ---------------- Amount
alcohol type I 15 ---------------- 225 ml
alcohol type II 95 ---------------- x ml
Mixture 80 ---------------- 225 + x ml
15 * 225 + 95 x = 80 ( 225 + x )
3375 + 95 x = 18000 + 80 x
95 x -80 x = -3375 + 18000
15 x = 14625
/ 15
x = 975 ml alcohol type II
