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How many liters of a 40% salt solutions must be added to a 4 liters of a 10% salt solutions to obtain 30% salt solutions?
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Let x be the required amount (volume) of a 40% salt solution.
Then the equation for the pure acid volume is
0.4x + 0.1*4 = 0.3*(x + 4).
Simplify and solve:
0.4x + 0.4 = 0.3x + 1.2,
0.4x - 0.3x = 1.2 - 0.4,
0.1x = 0.8,
x =
= 8.
Answer. 8 liters of 40% salt solution is needed.