SOLUTION: A chemist mixed some 15% peroxide solution ith some 6% peroxide solution to make 300 ML of a 9% peroxide solution. How many milliliters of the 15% solution was used?

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Question 101798This question is from textbook Algebra Introductory and intermediate
: A chemist mixed some 15% peroxide solution ith some 6% peroxide solution to make 300 ML of a 9% peroxide solution. How many milliliters of the 15% solution was used?
This question is from textbook Algebra Introductory and intermediate

Answer by stanbon(75887) About Me  (Show Source):
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A chemist mixed some 15% peroxide solution ith some 6% peroxide solution to make 300 ML of a 9% peroxide solution. How many milliliters of the 15% solution was used?
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Follow the active ingredient.
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15% solution DATA:
Amt = x ML ; amt of active ingredient = 0.15x ML
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6% solution DATA:
Amt = "300-x"ML ; amt of active ingredient = 0.06(300-x)= 18-0.06x ML
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9% Mixture DATA:
Amt = 300 ML; active = 0.09*300 = 27 ML
EQUATION:
active + active = active
0.15x + 18-0.06x = 27
0.09x = 9
x = 100 ML (amt of 15% solution needed in the mixture)
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Cheers,
Stan H.