SOLUTION: A chemistry teacher needs to mix a 30% salt solution with a 90% salt solution to make 25 qt of a 54% solution. How many quarts of each solution should the teacher mix to get the de
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A chemistry teacher needs to mix a 30% salt solution with a 90% salt solution to make 25 qt of a 54% solution. How many quarts of each solution should the teacher mix to get the de
Log On
Question 1016521: A chemistry teacher needs to mix a 30% salt solution with a 90% salt solution to make 25 qt of a 54% solution. How many quarts of each solution should the teacher mix to get the desired result? Found 2 solutions by ikleyn, stanbon:Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
A chemistry teacher needs to mix a 30% salt solution with a 90% salt solution to make 25 qt of a 54% solution.
How many quarts of each solution should the teacher mix to get the desired result?
---------------------------------------------------
It is a typical mixture word problem.
See the lesson Solving typical word problems on mixtures for solutions in this site, Problem 1.
This problem is very similar to yours.
In this lesson you will find the solution.
Consider it as a sample. Read it attentively.
Then solve your problem by substituting your data.
Good luck!
You can put this solution on YOUR website! A chemistry teacher needs to mix a 30% salt solution with a 90% salt solution to make 25 qt of a 54% solution. How many quarts of each solution should the teacher mix to get the desired result?
----------------
Quantity:: t + n = 25 qt
Salt::::: 30t+90n = 54*25
---------------------------------
Modify::
30t + 30n = 30*25
30t + 90n = 54*25
-------------
Subtract and solve for "n"::
60n = 24*25
------
n = 10 qts:: (amt. of 90%
t = 25-n = 15 qrs:: (amt. of 30% solution needed)
---------
Cheers,
Stan H.
(