SOLUTION: Scott wants to make a 31% saline solution. He has already poured 1 ml of a 82% saline solution into a beaker. How many ml of a 14% saline solution must he add to this to create the
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Question 1015663: Scott wants to make a 31% saline solution. He has already poured 1 ml of a 82% saline solution into a beaker. How many ml of a 14% saline solution must he add to this to create the desired mixture? Need the equation Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! Call the amount of 14% solution he needs to add, x. Then we set this up as
1(.82) + x(.14) = (1+x)(.31)
.82 + .14x = .31 + .31x
.51x = .17x
x = 3 mL of the 14% solution
