SOLUTION: a manufactu have 600l of 12% acid solution how many liters of 30% solution must be added to it so that acid content in the resulting mixture will be maximum then 15% nd less then 1

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Question 1015387: a manufactu have 600l of 12% acid solution how many liters of 30% solution must be added to it so that acid content in the resulting mixture will be maximum then 15% nd less then 18%
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean, LITERS, then use an abbreviation that cannot be misunderstood, like either L or the word, "liters".

Make a formula to use starting if possible, with all symbols, because you will compute twice - you want a range of values for how much of the 30% acid to use.

T, the target resulting value from 15% to 18% acid
v, how much of the 30% acid to use
You could choose to use only those as the variables.

%28600%2A12%2B30%2Av%29%2F%28v%2B600%29=T
Solve for v.

600%2A12%2B30v=T%28v%2B600%29
30v%2B600%2A12=Tv%2B600T
Tv%2B600T=30v%2B600%2A12
Tv-30v=600%2A12-600T
v%28T-30%29=600%2A12-600T
highlight%28v=%28600%2A12-600T%29%2F%28T-30%29%29

What is v for T=15?
What is v for T=18?
Those are the boundaries for v.