SOLUTION: One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of

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Question 1014127: One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?


Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water.
Change these ratios to percent salt in decimal form
2%2F%28%282%2B8%29%29 = .20 salt
and
3%2F%28%283%2B5%29%29 = .375 salt
:
How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?
Change to percent salt
3%2F%28%283%2B7%29%29 = .30 salt
:
Let x = amt of 37.5 % salt
then
(280-x) = amt of 20% salt
:
A typical mixture equation
.375x + .20(280-x) = .30(280)
.375x + 56 - .20x = 84
.375x - .20x = 84 - 56
.175x = 28
x = 28/.175
x = 160 qts of the 3:5 solution
and
280 - 160 = 120 qts of the 2:8 solution