Question 101204: A fuel distributor has 161,798 gallons of fuel with 1% sulfur content, which exceeds pollution control standards of 0.6% sulfur content. How many gallons of fuel oil with a 0.1% sulfur content must be added to the 161,798 gallons to obtain fuel oil that complies with the pollution control standards? Round up to the next higher gallon.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A fuel distributor has 161,798 gallons of fuel with 1% sulfur content, which exceeds pollution control standards of 0.6% sulfur content. How many gallons of fuel oil with a 0.1% sulfur content must be added to the 161,798 gallons to obtain fuel oil that complies with the pollution control standards? Round up to the next higher gallon.
-----------------------------
1% oil DATA:
Amt = 161,798 gals ; Amt of sulfur = 0.01*161,798 = 1617.98 gallons
---------------------
0.1% oil DATA:
Amt = x gals ; Amt of sulfur = 0.001x gallons
----------------------
0.6% Mixture DATA:
Amt = 161798+x ; Amt of sulfur = 0.006(161798-x) = 970.788 - 0.006x gals
-----------------------
EQUATION:
sulfur + sulfur = sulfur
1617.98 + 0.001x = 970.788 - 0.006x
647.192 = 0.005x
x = 129,438.4 gallons of 0.1% oil must be added to bring the tank down
to 0.6% sulfur content.
==============
Cheers,
Stan H.
|
|
|
