SOLUTION: A Certain Chain saw requires a fuel mixture of 5.5% oil and the remainder gasoline. How many liters of 2.5% mixture and how many of 9% mixture must be combined to produce 40.0 lit

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Question 100959This question is from textbook Technical Mathematics
: A Certain Chain saw requires a fuel mixture of 5.5% oil and the remainder gasoline. How many liters of 2.5% mixture and how many of 9% mixture must be combined to produce 40.0 liters of 5.5% mixture. This question is from textbook Technical Mathematics

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A Certain Chain saw requires a fuel mixture of 5.5% oil and the remainder gasoline. How many liters of 2.5% mixture and how many of 9% mixture must be combined to produce 40.0 liters of 5.5% mixture.
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5.5% mixture DATA:
Amount = 40 liters ; amt. of oil = 0.055*40= 2.2 liters
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2.5% mixture DATA:
Amt = x liters ; amt of oil = 0.025x liters
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9% mixture DATA;
Amt = 40-x liters; amt of oil = 0.09(40-x) = (3.6-0.09x) liters
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oil + oil = oil
3.6-0.09x + 0.025x = 2.2
-0.065x = -3.599 = -1.4
x = 21.538 liters (Amount of 2.5% mixture)
40-x = 18.462 liters (Amount of 9% mixture)
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Cheers,
stan H.