You can put this solution on YOUR website! How much water must be added to 200 liters of mixture which is 80 percent alcohol to reduce it to a 75 percent mixture ?
:
Amt of alcohol remains the same, therefore a simple equation
let w = amt of water to be added
.80(200) = .75(w+200)
160 = .75w + 150
160 - 150 = .75w
10 = .75w
w = 10/.75
w = 13 liters
:
:
Check this on your calc
.8(200) = .75(213.33)