SOLUTION: Hi, I've been stuck on this problem for a while. If anyone could help me I would really appreciate it! A solution contains 12 milliliters of alcohol and 15 milliliters of water.

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Question 1002772: Hi, I've been stuck on this problem for a while. If anyone could help me I would really appreciate it!
A solution contains 12 milliliters of alcohol and 15 milliliters of water. If another solution is to have the same concentration of alcohol in water but is to contain 25 milliliters of water, how much alcohol must it contain?
Thanks so much!
Found 3 solutions by fractalier, solver91311, MathLover1:
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Set up a proportion
12%2F15+=+x%2F25
Just multiply both sides by 25...
x+=+300%2F15+=+20
20 mL alcohol

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If you are stuck on the problem, you must have tried to solve it. Show what you have tried.

John

My calculator said it, I believe it, that settles it

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

if both solutions have the same concentration of alcohol in water, then we have a proportion

12 milliliters of alcohol : 15 milliliters of water=x milliliters of alcohol : 25 milliliters of water
or simply
12%2F15=x%2F25...solve for x
12%2A25=x%2A15
300=15x
x=300%2F15
x=20
another solution must contain 20 milliliters of alcohol