SOLUTION: Please help me solve this! Thank you in advance: How much water should be added to 10mL of a 10% acid solution to make it a 5% solution? .10(10) = .05(10+x) this is the equat

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Question 1002036: Please help me solve this! Thank you in advance:
How much water should be added to 10mL of a 10% acid solution to make it a 5% solution?
.10(10) = .05(10+x) this is the equation that i tried for please help if not right!

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You should figure by intuition that the answer quantity must be 10 mL.

You are adding water, which contains essentially no "acid".
%2810%2A10%29%2F%28w%2B10%29=5, a good way to setup the equation, but you appear to have picked decimal fractions instead of percents. Fine. That will be this way, instead:

%280.10%2A10%29%2F%28w%2B10%29=0.05

%280.10%2A10%29=0.05%28w%2B10%29

1.0=0.05w%2B0.5

1-0.5=0.05w

0.5=0.05w

%280.5%29%2F%280.05%29=w

w=50%2F5-----just to show a whole number denominator

highlight%28w=10%29

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Look for an arithmetic mistake in your steps.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me solve this! Thank you in advance:
How much water should be added to 10mL of a 10% acid solution to make it a 5% solution?
.10(10) = .05(10+x) this is the equation that i tried for please help if not right!
Your equation is correct! Good job!

You just need to continue to solve for x, the amount of water