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Question 1002017: Okay, so I'm working on Aleks, and they all of the sudden switched the problems I was working on and didn't give me an example on how to solve questions like these. I'm completely lost and stuck while trying to figure this out. Could someone please explain to me how I solve these types of questions?
Two factory plants are making TV panels. Yesterday, Plant A produced twice as many panels as Plant B. Four percent of the panels from Plant A and 3%of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 660 defective panels? Found 2 solutions by mananth, ikleyn:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website!
Let B produce x panels
Then A produces 2x panels
Four percent of the panels from Plant A and 3%of the panels from Plant B were defective.
0.04(2x) +0.03x = 660
0.08x +0.03x = 660
0.11x = 660
/0.11
x = 660/0.11
x= 6600
Panels produced by B are 6600
CHECK
4%(6600)+3%(13200) =660
You can put this solution on YOUR website! .
Two factory plants are making TV panels. Yesterday, Plant A produced twice as many panels as Plant B.
Four percent of the panels from Plant A and 3%of the panels from Plant B were defective.
How many panels did Plant B produce, if the two plants together produced 660 defective panels?
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Calculations and the answer in the post by @mananth are incorrect
His check is incorrect too - so, his check skipped the wrong answer.
I came to bring a correct solution.
Let B produce x panels
Then A produces 2x panels
Four percent of the panels from Plant A and 3%of the panels from Plant B were defective.
0.04(2x) +0.03x = 660
0.08x +0.03x = 660
0.11x = 660
/0.11
x = 660/0.11
x= 6000
Panels produced by B are 6000. ANSWER
CHECK
0.04(2*6000) + 0.03(6000) = 660. ! correct !