SOLUTION: How many gallons of a 30% hydrochloric acid solution and 80% hydrochloric acid solution must be mixed to get 20 gallons of a 50% hydrochloric acid solution.
so far i have tried th
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so far i have tried th
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Question 1000909: How many gallons of a 30% hydrochloric acid solution and 80% hydrochloric acid solution must be mixed to get 20 gallons of a 50% hydrochloric acid solution.
so far i have tried these two equations and than substituted:
30x+80y=50
x+y=20
and
.3x+.8y=.5
x+y=20
every time the answer end being (x=31,y=-11) as far as i see you cannot have a negative amount of the 80% solution. help... Answer by Edwin McCravy(20056) (Show Source):
You are forgetting to multiply the 50% or .5 by the 20 gallons
and you are only putting .5 instead of .5(20)
That is, you have this:
.3x+.8y=.5
x+y=20
but you should have this:
.3x+.8y=.5(20)
x+y=20
Now try it.
Edwin
