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This Lesson (How to approach math exam problems in general...especially with complicated words-with example) was created by by Alex.33(110)
  About Alex.33: Alex is back.
Let me show you how to approach most of your questions in exams mathodologically. Here's a simple example(simple enough so it's easy to see how it is): The sum of three numbers is -4. The second number decreased by the third is equal to the first. The sum of the first and the second number is -5. Find the numbers. Now let's start. 1..What we have? List out or number the cards at hand. (1)sum of three is -4. (2)the second number times 2/3 equals the first. (3)sum of the first two is -5. 2.What we want? Underline or wirte down our target. (Trust me,though it takes a little time for bigger problems you'll find it worthwhile) All three numbers. 3.Design approach using your knowledge. (Be CRYSTAL CLEAR what you're doing, and what makes doing which step applicable and safe...or what is the tradeoff) Use (1) and (3) to get the third. Use (2) and (3) to get the first and second. 4.Time to work!(Step by step. Do not skip...unless it's really really simple. Please be cautious.) f=first number s=second one t=third one t=(-4)-(-5)=1. s=2f/3 * s+f=-5 f=-3 s=-2 * Mark your answers with some easily identifiable mark. For example a highlighter, or just double underline.(Only do this if it's permitted) 5.(Optional)After you've done the question, double check using what you had in the first place. -2=-3*2/3 -2+(-3)=-5 -2+(-3)+1=-4 Correct. Finish this one. Now go and try apply it to any problem you have at hand. You'll find yourself clear and definite, with much less hesitation and much more confidence in just minutes or even seconds. This is what I call a basic problem solving logic. And this not only applys to math:It can apply to any problems since all of them share the same nature. Hope you have learned something from this and thanks for reading! This lesson has been accessed 1643 times. |
