Lesson Math Olympiad level problem on caves and bats

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Math Olympiad level problem on caves and bats


Problem 1

There is a mountain with  30  bat caves in a row that contain  340  bats,  in all.
Any  7  caves in a row contain exactly  77  bats.  Suppose the first cave has  7  times as many bats as the last cave.
How many bats are in the  29th cave?

Solution


Let me start my solution from the reference to an  Internet dictionary

            "in a row"  means  "in succession".

In this problem,  it is the only meanings of this term.


1.  Since any 7 caves in a row contain exactly 77 bats, we have, in particular

        a%5B1%5D%2Ba%5B2%5D%2Ba%5B3%5D%2Ba%5B4%5D%2Ba%5B5%5D%2Ba%5B6%5D%2Ba%5B7%5D = 77,   (1)

        a%5B2%5D%2Ba%5B3%5D%2Ba%5B4%5D%2Ba%5B5%5D%2Ba%5B6%5D%2Ba%5B7%5D%2Ba%5B8%5D = 77.   (2)


    Subtract equation (1) from equation (2).  The terms from a%5B2%5D to a%5B6%5D will cancel each other, and you will get

        a%5B8%5D - a%5B1%5D = 0,   or

        a%5B1%5D = a%5B8%5D.


    Making the same step by step, you will get

        a%5B2%5D = a%5B9%5D,
        a%5B3%5D = a%5B10%5D,
        a%5B4%5D = a%5B11%5D,
        a%5B5%5D = a%5B12%5D,
        a%5B6%5D = a%5B13%5D,
        a%5B7%5D = a%5B14%5D,
        a%5B8%5D = a%5B15%5D = a%5B1%5D

    and so on. It means that the sequence  a%5B1%5D, a%5B2%5D, a%5B3%5D, . . . , a%5B30%5D is PERIODICAL with the period 7.


    It is the FIRST IDEA of the solution.



2.  Its consequence is that  a%5B1%5D = a%5B29%5D.


    Therefore, from the condition, we have this equation

        a%5B1%5D = a%5B29%5D = 7%2Aa%5B30%5D.     (3)


    It is the SECOND IDEA of the solution.



3.  From the condition, we have 

        a%5B1%5D%2Ba%5B2%5D%2Ba%5B3%5D%2Ba%5B4%5D%2Ba%5B5%5D%2Ba%5B6%5D%2Ba%5B7%5D = 77,

        a%5B8%5D%2Ba%5B9%5D%2Ba%5B10%5D%2Ba%5B11%5D%2Ba%5B12%5D%2Ba%5B13%5D%2Ba%5B14%5D = 77,

        a%5B15%5D%2Ba%5B16%5D%2Ba%5B17%5D%2Ba%5B18%5D%2Ba%5B19%5D%2Ba%5B20%5D%2Ba%5B21%5D = 77,

        a%5B22%5D%2Ba%5B22%5D%2Ba%5B24%5D%2Ba%5B25%5D%2Ba%5B26%5D%2Ba%5B27%5D%2Ba%5B28%5D = 77.

    since any 7 caves in a row contain exactly 77 bats.


    Add these 4 equation (both sides). You will get

        a%5B1%5D + a%5B2%5D + a%5B3%5D + . . . + a%5B28%5D = 4*77 = 308.


    It means that  

        a%5B29%5D + a%5B30%5D = 340 - 308 = 32.    (4)


    It is the THIRD IDEA of the solution.



4.  Now, from equations (3) and (4) we have

        a%5B30%5D + 7%2Aa%5B30%5D = 32.


    It implies  8%2Aa%5B30%5D = 32,   or


        a%5B30%5D = 32/8 = 4.


    Hence,  a%5B29%5D = 7%2Aa%5B30%5D = 7*4 = 28.


ANSWER.  a%5B29%5D = 28.  The 29-th cave has 28 bats.


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