SOLUTION: Bob buys Halloween candy. Some pieces cost 2¢ each and some cost 5¢ each. There are 7 more of the 2¢ pieces. The total cost was $1.54. How many 5¢ pieces were purchased?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Bob buys Halloween candy. Some pieces cost 2¢ each and some cost 5¢ each. There are 7 more of the 2¢ pieces. The total cost was $1.54. How many 5¢ pieces were purchased?      Log On

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Question 999681: Bob buys Halloween candy. Some pieces cost 2¢ each and some cost 5¢ each. There are 7
more of the 2¢ pieces. The total cost was $1.54. How many 5¢ pieces were purchased?

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Same as a mixture problem.

x, how much 2cent pieces
y, how much 5cent pieces

system%28x=y%2B7%2C2x%2B5y=154%29
This is apparently a simple linear system application for counts of items and the cost of a combination of those items. Note very carefully that the cost account equation is in units of CENTS, not dollars.

You can make the substitution in the system.
2%28y%2B7%29%2B5y=154
2y%2B14%2B5y=154
7y=154-14
7y=140
highlight%28y=20%29-------the count of the 5 cent pieces.