SOLUTION: A stone is thrown vertically upward from the roof of a building. The formula that describes the height h (in feet) of the stone after "t" seconds is given below. h=-16t^2+64t+40

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Question 993401: A stone is thrown vertically upward from the roof of a building. The formula that describes the height h (in feet) of the stone after "t" seconds is given below.
h=-16t^2+64t+40
How many seconds after the stone is thrown would it reach for the first time 100 feet in height?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A stone is thrown vertically upward from the roof of a building. The formula that describes the height h (in feet) of the stone after "t" seconds is given below.
h=-16t^2+64t+40
How many seconds after the stone is thrown would it reach for the first time 100 feet in height?
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h=-16t^2+64t+40 = 100
Solve for t.
There might be 2 solution, ascending and descending.