SOLUTION: A man spends money according to the date. Eg: On 15th he will spend 15rs, 19th he will spend 19rs. One night he will count 5 consecutive days and the amount equals to 61. W

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Question 988618: A man spends money according to the date.
Eg: On 15th he will spend 15rs, 19th he will spend 19rs.
One night he will count 5 consecutive days and the amount equals to 61.
What are those 5 consecutive dates?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The five consecutive dates are:
February 27, February 28, March 1, March 2, and March 3 of a year that is not a leap year.
Five consecutive days often will be in the same month and hence consecutively numbered, as in
n-2 , n-1 , n , n%2B1 , and n%2B2 , which add up to
n-2%2Bn-1%2Bn%2Bn%2B1%2Bn%2B2=5n , so the sum would be a multiple of 5.
Since 61 is not a multiple of 5,
the 5 consecutive days must include the end of a month and the beginning of the next month.
If the first month 30 or 31 days,
the possible sums do not add up to 61 :
30%2B31%2B1%2B2%2B3=67 , 31%2B1%2B2%2B3%2B4=41 ,
29%2B30%2B1%2B2%2B3=65 , 30%2B1%2B2%2B3%2B4=40 .
So, the first month must be February, with 28 or 29 days.
Since 28%2B2=30 and 27%2B3=30,
the sum 27%2B28%2B1%2B2%2B3=61 works.
The other possibility with two days in February and three in March,
29%2B28%2B1%2B2%2B3=63 , yields a sum that is too high,
and using only one day from February will yield too low a sum.