SOLUTION: A house has two rooms of equal area. One room is square and the other room is rectangle 5 ft narrower and 6ft longer than the square one. Find the area of each room.

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Question 988323: A house has two rooms of equal area. One room is square and the other room is rectangle 5 ft narrower and 6ft longer than the square one. Find the area of each room.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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S=side of square; L=length of rectangle=S+6ft; W=width=S-5ft
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Areas are the same:
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S%5E2=LW
S%5E2=%28S%2B6%29%28S-5%29%0D%0A%7B%7B%7BS%5E2=S%5E2%2BS-30
0=S-30
30=S The sides of the square are 30 feet.
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A=S^2=(30 ft)^2=900ft^2
ANSWER: The area of each room is 900 square feet.
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CHECK:
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LW=Area
(S+6ft)(S-5ft=)=900ft^2
(30ft+6ft)(30ft-5ft)=900ft^2
(36ft)(25ft)=900ft^2
900ft^2=900ft^2