SOLUTION: A minor league baseball team had a total attendance one evening of 1175, the tickets for adults and children sold for 5.00 and 3.50 respectively , the ticket revenue that night was
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Question 986487: A minor league baseball team had a total attendance one evening of 1175, the tickets for adults and children sold for 5.00 and 3.50 respectively , the ticket revenue that night was 5087.50 . create a system of linear equations to find the numbers of adults A and children C at the game, and solve your system of equations by elimination or by substitution . explain your choice m use the intersact feature or the zoom and trace features of a graphice utility to solve your syetem Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
A+C=1175
A=1175-C
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$5.00A+$3.50C=$5087.50
$5.00(1175-C)+$3.50C=$5087.50
$5875-$5.00C+$3.50C=$5087.50
-$1.50C=-$787.50
C=525 ANSWER 1: There were 525 children at the game.
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A=1175-525
A=650 ANSWER 2: There were 650 adults at the games.
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CHECK:
$5.00A+$3.50C=$5087.50
$5.00(650)+$3.50(525)=$5087.50
$3250+$1837.50=$5087.50
$5087.50=$5087.50
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A is on x axis, C is on y axis
A+C=1175 (Red line on graph)
$5.00A+$3.50C=$5087.50 (Green line on graph)
.
.
Intersection at (650,525)
