SOLUTION: One number is 2 Times another. If you subtract 10 from each number, the sum is 40, what are the numbers?

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Question 9783: One number is 2 Times another. If you subtract 10 from each number, the sum is 40, what are the numbers?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the 1st number and y be the 2nd number.
Then:
x+=+2y and
%28x-10%29+%2B+%28y-10%29+=+40 Substiute x = 2y from the 1st equation.
%282y-10%29+%2B+%28y-10%29+=+40 Simplify and solve for y.
3y+-20+=+40 Add 40 to both sides.
3y+=+60 Divide both sides by 3.
y+=+20
x+=+2y
x+=+2%2820%29
x+=+40
Check:
x+=+2y
40+=+2%2820%29
and:
%28x-10%29+%2B+%28y-10%29=+%2840-10%29+%2B+%2820-10%29 = 30+%2B+10+=+40