SOLUTION: Hello, I really need help in this question. Please help? Thank you so much. ..... On a road trip, a family drives one third of the way on the first day. After driving 200 miles o

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hello, I really need help in this question. Please help? Thank you so much. ..... On a road trip, a family drives one third of the way on the first day. After driving 200 miles o      Log On

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Question 970515: Hello, I really need help in this question. Please help? Thank you so much.
.....
On a road trip, a family drives one third of the way on the first day. After driving 200 miles on the second day, they are seven ninths of the way to their destination. How many miles is there trip?
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I think,although I'm not 100% positive, that the 200 miles are 4/9 of the way. Therefore, once you add the 1/3 you have 7/9. Meaning that they still need to drive 2/9 of the way. I don't know what to do next... your help would be greatly appreciated. Thank you.
Found 2 solutions by rfer, ankor@dixie-net.com:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
7/9-3/9=4/9 2nd day
200/(4/9)=
200*9/4=1800/4=450 mi total

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
On a road trip, a family drives one third of the way on the first day.
After driving 200 miles on the second day, they are seven ninths of the way to their destination. How many miles is there trip?
:
Here is the equation for what you basically said
let d = total dist of the trip
d = 1%2F3d + 200 + 2%2F9d
d = 3%2F9d + 200 + 2%2F9d
d = 5%2F9d + 200
d - 5%2F9d = 200
4%2F9d = 200
d = 200 * 9%2F4
cancel 4
d = 50 * 9
d = 450 mi