Question 937834: The salsburgs are moving to pennsylvania. If the father leaves at 5 A.M., driving a large moving truck at 55 mph , and his son leaves at 6:30 A.M. in a van averaging 65 mph, at what time will the son catch up with his father ? Will they be able to eat lunch together ?
can you please give an equation and detailed explanation
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The salsburgs are moving to pennsylvania. If the father leaves at 5 A.M., driving a large moving truck at 55 mph , and his son leaves at 6:30 A.M. in a van averaging 65 mph, at what time will the son catch up with his father ? Will they be able to eat lunch together ?
can you please give an equation and detailed explanation
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Father DATA:
rate = 55 mph ; time = x hrs ; distance = r*t = 55x miles
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Son DATA:
rate = 65 mph ; time = x-(3/2) hrs ; distance = 65(x-(3/2)) miles
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Equation:
distance = distance
55x = 65x - (3/2)65
-10x = -(3/2)65
x = (3/2)6.5
x = 9.75 hrs
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5 AM + 9.75 hrs = 2:45 PM (time they can get together for lunch)
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