SOLUTION: A certain number is expressed by three digits whose sum is 14. If 693 is added to the number, the digits will appear in reverse order. If the units digit is equal to the tens digit

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Question 937024: A certain number is expressed by three digits whose sum is 14. If 693 is added to the number, the digits will appear in reverse order. If the units digit is equal to the tens digit increased by 6 , what is the number ?
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
Please excuse; a solution post was here but incorrect. Mistake in my description analysis. You should repost.

THIS IS BETTER:
You are looking for some number, 100h%2B10t%2Bu.

Retried but unfinished:
The first and last part of the description give a system
system%28h%2Bt%2Bu=14%2Cu=t%2B6%29
-
Use h as just an unknown constant. Working with the system you can get
system%28t%2Bu=14-h%2Ct-u=-6%29

Working with that system you can find these formulas:
highlight_green%28t=4-h%2F2%29
and
highlight_green%28u=10-h%2F2%29
That tells you something about h and about the other two variables but does not finish solving; the middle sentence description of adding the 693 is still possibly needed...

Here are the possibilities.
.
h must be a even digit only(or should zero be included?). Nothing else. Zero cannot be used because there is no "10" digit.
h______t_____u
2______3_____9
4______2_____8
6______1______9
8______X_____6

Clearly, there are THREE possibilities. You can check how each of the three possibilities either satisfy the middle description or not.

The one which works is the first one in the table:
239.

You find that 239+693=932.